Hi folks,
I did this way:
Step1->send 1-6 first together
Step2à send back 1
Step3à send 3 and 1 together
Step4à send back 1
Step5à send 12 and 8(this is a critical step)
Step6à send back 3
Step 7àsend 1 and 3(game over)
In total 29 seconds
easy naa!!!
From India, New Delhi
I did this way:
Step1->send 1-6 first together
Step2à send back 1
Step3à send 3 and 1 together
Step4à send back 1
Step5à send 12 and 8(this is a critical step)
Step6à send back 3
Step 7àsend 1 and 3(game over)
In total 29 seconds
easy naa!!!
From India, New Delhi
Dear firend, :) :oops: :twisted: :evil: :oops: Those were me for long time! And then solution hit me like this :idea: :D It’s Good one! Awaiting 4 more! JOYFUL!
From India, Mumbai
From India, Mumbai
Hey Guys,
Anybody can solve this puzzle, actually out of 5 rules 1 is wrong "A pair must walk together at the rate of the slower person" . and in this way we get conditioned that pair has to walk together so we cant be able to solve it..
while solving the puzzle it is not so.
I have solved it in 29 sec.
Regs,
Nidhi
From India, Jaipur
13Anybody can solve this puzzle, actually out of 5 rules 1 is wrong "A pair must walk together at the rate of the slower person" . and in this way we get conditioned that pair has to walk together so we cant be able to solve it..
while solving the puzzle it is not so.
I have solved it in 29 sec.
Regs,
Nidhi
From India, Jaipur
I solved this in 3 attempts...
Here giving the answer for whom who tried really hard, or who assumes it is mathmatically impossible.
Here we find 5 charactors with the speed of 1,3,6,8,12 right!! and at a time two can go....
Try this one (WE name charactors according to thier moving speed)
1... 1 and 3 will go (3 Second)
2... 1 will come back (1 Second)
3...8 and 12 will go...(12 second)
4...3 will come back (3 second)
5. 1 and 6 will go (6 second)
6. 1 will come back (1 second)
7. 1 and 3 will go ( 3 second)
Total 29 second and 1 second remains.
Cheers!!! :lol: :lol: :lol:
From India, Calcutta
Here giving the answer for whom who tried really hard, or who assumes it is mathmatically impossible.
Here we find 5 charactors with the speed of 1,3,6,8,12 right!! and at a time two can go....
Try this one (WE name charactors according to thier moving speed)
1... 1 and 3 will go (3 Second)
2... 1 will come back (1 Second)
3...8 and 12 will go...(12 second)
4...3 will come back (3 second)
5. 1 and 6 will go (6 second)
6. 1 will come back (1 second)
7. 1 and 3 will go ( 3 second)
Total 29 second and 1 second remains.
Cheers!!! :lol: :lol: :lol:
From India, Calcutta
Hi, first AB go B comes back = 3+3=6 DE go A comes back = 12+1=13 AC go A comes back = 1+6=7 AB go 3+1 =4 total 30 secs Very ineresting, enjoyed a lot. thanks for sharing
From India, Bangalore
From India, Bangalore
Hello, Can u post the answer for Me.. I tried a lot but could not get the answer. Regards, Jyothi
From India, Bangalore
From India, Bangalore
[quote="Jyothi13"]Hello,
Can u post the answer for Me.. I tried a lot but could not get the answer.
Regards,
Jyothi[/quote
Hi Jyoti,
move A,B then leave A and B should come back, 3+3 = 6 s
Let D,E move then A will come back, 12 + 1 =13 s
A,C will go then Awill come back, 6+1 =7
A, B will go , 3 s.
So 1 sec will remain.
From India, Bangalore
Can u post the answer for Me.. I tried a lot but could not get the answer.
Regards,
Jyothi[/quote
Hi Jyoti,
move A,B then leave A and B should come back, 3+3 = 6 s
Let D,E move then A will come back, 12 + 1 =13 s
A,C will go then Awill come back, 6+1 =7
A, B will go , 3 s.
So 1 sec will remain.
From India, Bangalore
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